
Yefim S. answered 06/13/22
Tutor
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(20)
Math Tutor with Experience
Maximum energy W = kx2/2 = 500N/m·0.04 m2/2 = 10 J
James A.
asked 06/13/22How much energy can be stored in a spring with k = 500 N//m if the maximum possible stretch is 20 cm ?
Yefim S. answered 06/13/22
Math Tutor with Experience
Maximum energy W = kx2/2 = 500N/m·0.04 m2/2 = 10 J
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