An aluminum wing on a passenger jet is 27 m long when its temperature is 27°C. At what temperature would the wing be 7 cm (0.07 m) shorter

Answer 1

The equation to be used is ΔL = α L₀ (t_final - t_initial) where α = 25.5 x 10^-6 /C°.

Solve for t_final = (ΔL + α L₀ x t_initial ) / α L₀ = (-0.07m + 25.5 x 10^-6 /C°x 27m x 27 C°) / ( 25.5 x 10^-6 x 27m)

= -75° C