find the equation of the line in slope-intercept form that passes through the following point (-2,-12) with the given slope of -4/3

Answer 1

y - y₁ = m (x - x₁) m= -4/3

(-2,-12) x_{1= -2} y_{1= -12}

_{y - (-12) = (-4/3) (x- (-2))}

_{y + 12 = -4/3( x+2)}

_{y + 12 = (-4/3)x +(-4/3)(2)}

_{y + 12 = (-4/3)x - 8 /3}

-12= -12

y= (-4/3)x - 12 - 8/3

y=-(-4/3)x - 12(3/3)- 8/3

y = (-4/3)x -36/3 - 8/3

y=(-4/3)x - 44/3

Answer 2

The slope-intercept form is y = mx + b.

slope = m = -4/3, so the equation is now y = (-4/3) x + b

passing through the point (-2, -12) means that when x = -2 we have that y = -12,

so we now have the equation -36/3 = -12 = y = (-4/3) x + b = (-4/3) (-2) + b = 8/3 + b, so b = -44/3.

Finally, we have the following equation: y = (-4/3) x + (-44/3).