Raymond B. answered 06/07/22
Math, microeconomics or criminal justice
1/x is a rectangular hyperbola
for x<-1 it's part of the lower branch of the hyperbola
x^2 -2 is an upward opening parabola
the parabola and hyperboal meet at x=-1
the stepwise function is continuous at all points for all values of x including x=0
You might be tempted to compare the hyperbola to the parabola at x=0,
where the parabola is at its y intercept (0,-2) and the hyperboal is undefined, approaching negative infinity, but that ignores the fact that the stepwise function at x=0 is entirely continuous since only the parabola is relevant at x=0.