Raymond B. answered 06/07/22
Math, microeconomics or criminal justice
1 continuous
2 discontinuity
3 discontinuity
4 continuous
5 continuous
2 and 3 involve division by zero, which is undefined. The graphs are undefinied at the place where x=2 for number 2, and where x=1 for number 3
both 2 and 3 are rectangular hyperbolas with two separate branches. at the given x values, the branches are separate. the graphs go from negative infinity then jump to positive infinity.
1 3x^2 +2x +1 is an upward opening parabola with y intercept = 1. At x=-2, f(x) = y=6
the parabola is continuous at all values of x including x=-2
5 is a similar upward opening parabola, continuous at all x values
4 is log(x^2-3) = log(2^2-3) = log(4-3) = log(1) = 0
it's a function that's continuous for all values of x>sqr3 as that makes f(x) = log(0) for x=sqr3 which is undefined. Any x<sqr3 makes f(x) = log(negative number) which is also undefined.