Stephen H. answered 06/03/22
Tutor of Math, Physics and Engineering ... available online
The total power consumed = 230+250+200 = 680 watts. The total current = 680/140=4.86 amp and is the current through the single series resistance. This resistance = P/I2 = 230/4.862= 9.74 ohms = Rseries. The voltage across Rseries = 9.74*4.86= 47.3 volts leaving the voltage across the parallel combination to be 140-47.3= 92.7 volts. The power consumed by one of the parallel resistances = 92.72/R2=250watts, thus R2= 34.4 ohms. The oower consumed by the other parallet resistance = 92.72/R3=200 watts, thus R3= 43 ohms