Raymond B. answered 05/26/22
Math, microeconomics or criminal justice
(-T+C)/(1-S) = 1/C
T=Tant S=Sint C=Cost, Sect = 1/Cost
and Tant = Sint/Cost, T=S/C
(-S/C +C)/(1-S) = 1/C
multiply both sides by C(1-S) to eliminate the fractions and get
-S +S^2 +C^2 = 1-S
replace C^2= 1-S^2
and cancel the -S terms on both sides
S^2 + 1-S^2 = 1
1=1
QED.
it's an identity, true for any angle
or you may have intended to write
-tant + (cost)/(1+sint) = sect? which is technically the way it's written
then
-sint/cost + cost/(1-sint) = 1/cost
multiply by cost
-sint + cos^2(t)/(1-sint) = 1
multiply by 1+sint
-sint -sin^2(t) + cos^2(t) = 1 + sint
replace cos^2(t) with 1-sin^2(t) (the Pythagorean Theorem cos^2(t) + sin^2(t) = 1)
-sint -sin^2(t) + 1 - sin^2(t) = 1 + sint
the 1's cancel leaving
-sint - 2sin^2(t) = sint
-2sin^2(t) -2sint = 0
divide by -1
2sin^2(t) +2sint = 0
divide by 2
sin^2(t) +sint = 0
sint(sint +1) = 0
sint = 0 or -1
t = 0, 180 or 270 degrees, or pi or 3pi/2 radians
which is not a trig identity
just one counterexample will prove it's not a trig identity
try t=45 degrees
(-tan45+cos45)/(1-sin45) = sec45
= about (-1 +.71)/(1-.71) = 1/.71
= (-.29)/.29 doesn't = 1/.71 because the sign is different
if an equation isn't true for all, it's Not an identity
try the other possible interpretation of the problem, with 45 degrees
-tant + cost/(1-sint) = sect
=-tan45 + cos45/(1-sin45) = sec45
-1 + .71/(1-.71) = 1/.71
-1 + .71/.29 = 1/.71
-1 + 2.4 = 1.4
it seems to work
try t= 30
-tan30 + cos30/(1-sin30) = sec30
-1/sqr3 + (sqr3/2)/(1-1/2) = 1/(sqr3/2)
-1/sqr3 + sqr3 = 2sqr3/3
-sqr3/3 + 3sqr3/3 = 2sqr3/3
2sqr3/3 = 2sqr3
It looks like a trig identity. so there's an error in the calculations above, somewhere. One way or the other.
Steven L.
What identity did you use to simplify the fraction at the end.05/26/22