¬ simply exchanges ∃ and∀, ∧ and ∨
¬∃x (∀y∃tS(x, y, t) ∧ ∃tR(x, t)) = ∀x (∃y∀t¬S(x, y, t) ∨ ∀t¬R(x, t))
Isaac H.
asked 05/23/22Rewrite the statement ¬∃x (∀y∃tS(x, y, t) ∧ ∃tR(x, t)) so that negations appear only within predicates.
¬ simply exchanges ∃ and∀, ∧ and ∨
¬∃x (∀y∃tS(x, y, t) ∧ ∃tR(x, t)) = ∀x (∃y∀t¬S(x, y, t) ∨ ∀t¬R(x, t))
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