escape velocity

Question

The escape velocity of a bullet from the surface of planet Y is 1951.0 m/s. Calculate the escape velocity from the surface of the planet X if the mass of planet X is 1.35 times that of Y, and its radius is 0.871 times the radius of Y.

Answer 1

Escape Speed:

The minimum speed with which an object to be thrown from a planet, so that it never returns back to the planet is termed as escape speed. The magnitude of the escape speed depends on the mass and radius of the planet.

Vescape = sqrt ( 2Gm/R)

1983 = sqrt ( 2Gm/R)

=> sqrt ( 2G*1.35m/0.807*R) = 1.29*1983 = 2558.07 m/s ( escape velocity from the surface of the planet X )