Torque /Physic related problem

Question

To turn a nut, a wrench must create

2.25 N*m of torque. If the person

exerts a 48.3 N force perpendicular to

the wrench, how far from the nut

should the force be applied?

Can someone please give me a thorough answer ?

Answer 1

For your torque problems, it's helpful to think with the mentality of how far and how much? Meaning how far from your fulcrum (d = distance) and how much meaning what is the force that's been applied (F = Force)?

For this problem, we would use the equation Torque = F * d * sin (Θ)

Based on the information from the problem, we know the following:

F = 48.3 N

d = x

Torque = 2.25 Nm

Θ = 90^o

When I replace these values, I calculate using the following:

2.25 = 48.3 * x* sin (90)

remember the sine of 90 degrees or a perpendicular angle is 1

2.25 = 48.3* x* 1

0.0466 m = x

Also, note that your distance is in meters in this formula. Your answer would be in 0.0466 m but 46 centimeters.