Daniel B. answered  05/13/22
A retired computer professional to teach math, physics
Let,
m = 2 kg be the mass of the disk,
R = 0.75 m be the radius of the disk,
F be the force applied to the edge (different for questions a and b),
θ be the angle of displacement (different for questions a, b, and c),
k be the torsion constant (to be calculated).
The term "torsion constant" can have different meanings.
Here it apparently means
torsion constant = torque/(angle of displacement)
a)
F = 65 N
θ = 1.4 rad
The torque
τ = RF
The torsion constant
k = τ/θ = RF/θ = 0.75×65/1.4 = 34.82 Nm/rad
b)
θ = 2π
τ = kθ = 34.82×2π = 218.79 Nm
c)
Let
θ(t) be the angle of twist at time t,
α(t) be the angular acceleration at time t,
τ(t) be the torque the wire applies to the disc at time t,
I = mR²/2 be the moment of inertia of the disk.
The disc follows Newton's Second Law applied to rotation:
τ(t) = Iα(t) (1)
The torque τ(t) is proportional to the angle θ(t), but in the opposite direction:
τ(t) = -kθ(t) (2)
Combining (1) and (2)
Iα(t) = -kθ(t)
I do not know what mathematical tools are at your disposal, but this is a
differential equation
d²θ/dt² = -(k/I)θ
This equation has the solution
θ = Asin(2πft + φ),
where the amplitude A and the phase φ are determined from initial conditions, and
the frequency
f = (1/2π)√(k/I) = (1/2π)√(k/(mR²/2)) = (1/2πR)√(2k/m)
Substituting actual numbers
f = (1/(2×π×0.75))√(2×34.82/2) = 1.25 rad/sec
    
            
 A uniform disc of mass