Eugene E. answered 05/11/22
University Physics, Electrodynamics, and Quantum Mechanics Tutor
His linear velocity equals his angular velocity times his distance from the center of the merry-go-round, that is, (2.38 rad/s)(1.74 m) = 4.14 m/s.
Jordan M.
asked 05/11/22A kid is standing on a
merry-go-round, 1.74 m from
the center, rotating at 2.38 rad/s
What is his linear velocity?
Could someone answer this thourgly ?
Eugene E. answered 05/11/22
University Physics, Electrodynamics, and Quantum Mechanics Tutor
His linear velocity equals his angular velocity times his distance from the center of the merry-go-round, that is, (2.38 rad/s)(1.74 m) = 4.14 m/s.
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