Robert C. answered 05/11/22
Physics Grad with 3+ years Tutoring experience
Young's modulus, E, is given by the equation E = σ/ε, where σ = F/A, and ε = ΔL/L0, giving E = (F/A)/(ΔL/L0) = L0F/(AΔL). F is force, A is cross sectional area, L0 is the original length, and ΔL is the change in length. We need to rearrange for ΔL to get ΔL = L0F/(EA) = (53mm*2.5N)/(1.0x109 N/m2 * π * (.35/2mm)^2) = .00138m or 1.38mm.