Rectangular form to polar

Question

(2,2sqrt3) to polar form

Answer 1

(4 pi/3) or (4, 60) in polar form for x=2, y=2sqr3

x=rcos(theta), y=rsiin(theta)

r = x/cos(theta)=2/1/2 = 4

r= y/sin(theta) =2sqr3/sqr3/2 = 4

(2, 2sqr3) has a 60 degree angle

tan(theta) = 2sqr3/2 = sqr3

theta = 60

r^2 = x^2 + y^2

hypotenuse squared = 2^2 + (2sqr3)^2 = 4 +12= 16

hypotenuse = sqr16 = 4 = r