Angles using sin and cosine

Question

Angle A=2

side a= 1000

find side b

Answer 1

b/sinB = a/sinA

b = asinB/sinA

b = 1000sinB/sin2

b = 2,865.37sinB

-1 < sin B < 1

-2,865.37 < b < 2,865.37 but b>0, all lengths are positive distances

0 < B < 180-15

0 < B < 165

so

0 < b < 2,865.37

the closer B is to 90 degrees the closer b is to 2,865.37

the closer B is to 0 degrees, the closer b is to 0

the closer B is to 165 degrees, the closer b is to 741.6

maximum b is when

b' = 2865.37(cosB) = 0

cosB = 0

B = 90 degrees

this all assumes you meant A = 2 degrees,

if you meant A = 2 radians, then A = about 114.6 degrees

then

b = 1000sinB/sin114.6

= about 1020sinB

B >0

B< 180-114.6

B< 65.4

max b = about 1020

min b = 0

0 < b < 1020