Acting Normal Force

Question

A 15.0 kg crate sits on a 20.0 kg table, which sits on the floor. What is the normal force acting on the crate?

Answer 1

The magnitude of gravitational force on the table-crate system will be equal to

(m(table + m(crate))g = (15.0+ 20.0) x 9.81 = 343N

Hence, normal force acting on the crate is 343 N.

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