If q1 and q2 have the same charge of 60 µC with a magnitude of the force between them is 500 N, what is the distance separated these two charges?

Answer 1

Using Columb's Law: F=Kq1q2/r^2 you can rearrange the formula so that r=√kq1q2/f

This will give you r= √(8.99x10^9)(60x10^-6)(60x10^-6/(500)

After doing the math r=.254 meters