
Bryan J. answered 05/01/22
Down-to-earth Physics and Math tutor with a PhD
Analogous to projectile motion in the presence of constant gravitational acceleration, the angular displacement under constant angular acceleration is given by
θ = θ0 + ω0t + 0.5αt2
The time derivative of this expression gives
a) ω = ω0 + αt = 3.5 + 8.5t
b) ω = 3.5 + 8.5(25) = 216 rad/s
c) θ = 3.5t + 4.25t2 (expression above with θ0 = 0)
d) θ = 3.5(25) + 4.25(25)2 = 2743.75 rad