A rectangular plot is to be fenced in with 100 meters of fencing. If the area of the plot is 609 square meters, what are its dimensions?

Answer 1

Perimeter = 2(L+2W) = 100

L+2W = 50

Area of 609 = WL

L=609/W

609/W + 2W = 50

609 +2W^2 = 50W

2W^2 -50W - 609 = 0

W = 50/4 + (1/4)sqr(2500 +8(609))

W = (50 + 85.86)/4

W = 135.86/4 = 21.47 meters Width

L = 609/21.47 = 28.37 meters Long

Area = WL = 21.47 x 28.37 = 609.10 = 609 m^2 rounded off to nearest integer

Perimeter = 2(W+L) = 2(21.47+28.37) = 2(49.84) = 99.68 = 100 m. rounded off to nearest integer