Assuming volume, V, is constant, the length of an elliptical solid being sheared varies directly as the square of the radius and inversely as the width. If a solid with a width of 10 cm and radius of 10 cm has a length of 2 cm, what is the length of a solid with a radius of 15 cm and width of 18 cm?
The problem generates an equality which is:
r2 = 15 cm; r1 = 10 cm; w2=18 cm;w1= 10 cm; L1=2 cm
Plugging this values in the formula, we obtain:
L2=(225/180)*2 = 2.5 cm
Having V as a constraint or boundary conditions all the parameters will be governed by the given proportions.