Assuming volume, V, is constant, the length of an elliptical solid being sheared varies directly as the square of the radius and inversely as the width. If a solid with a width of 10 cm and radius of 10 cm has a length of 2 cm, what is the length of a solid with a radius of 15 cm and width of 18 cm?

The problem generates an equality which is:

(L2/L1)=(r2

^{2}/r1^{2})*(w1/w2)Here

r2 = 15 cm; r1 = 10 cm; w2=18 cm;w1= 10 cm; L1=2 cm

Plugging this values in the formula, we obtain:

L2=(225/180)*2 = 2.5 cm

Having V as a constraint or boundary conditions all the parameters will be governed by the given proportions.

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