Range = (v02/g) * sin(2θ0)
Max height = vy02/(2g) note that it is vy0 = v0sin(θ0)
Time in the air = 2vy0/g
Ren S.
asked 04/29/22A projectile was launched with an initial velocity of 4 ms from a height of 8 meters at an angle of 40-
degrees from the horizontal. Calculate the (a) Total Range, (b)Total time of flight and (c) Maximum
height reached by the projectile.
Range = (v02/g) * sin(2θ0)
Max height = vy02/(2g) note that it is vy0 = v0sin(θ0)
Time in the air = 2vy0/g
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.