In the figure R1 = 5.65 Ω, R2 = 17.0 Ω, and the ideal battery has emf ε = 13.5 V. (a) What is the magnitude of current i1? (b) How much energy is dissipated by all four resistors in 2.36 min?

Question

In the figure R₁ = 5.65 Ω, R₂ = 17.0 Ω, and the ideal battery has emf ε = 13.5 V. (a) What is the magnitude of current i₁? (b) How much energy is dissipated by all four resistors in 2.36 min?

Answer 1

A) R = R₁ + R₂/3 = 5.65 + 17/3 = 11.32 Om

i₁ = ε/R = 13.5 V/11.32 Om = 1.19 A

B) Energy W = i·ε·t = 1.19·13.5·2.36·60 = 2275 J