Mark M. answered 04/25/22
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
Draw and label a diagram!
z = 0 - 2πi
||z|| = 2π
θ = 3π / 2
z = 2π(cos (3π / 2) + i sin (3π / 2))
Madison P.
asked 04/25/22
Mark M. answered 04/25/22
Mathematics Teacher - NCLB Highly Qualified
Draw and label a diagram!
z = 0 - 2πi
||z|| = 2π
θ = 3π / 2
z = 2π(cos (3π / 2) + i sin (3π / 2))
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