Inactive Tutor answered 04/24/22
Tutor
New to Wyzant
sin2x = 2sinxcosx, tanx = sinx/cosx, cotx = cosx/sinx
sin2x(tanx+cotx)
=2sinxcosx(sinx/cosx + cosx/sinx)
=2(sin^2(x) +cos^2(x))
=2(1)
= 2
Mohammed M.
asked 04/24/22Sin 2x(tan x + cot x)= 2
Inactive Tutor answered 04/24/22
sin2x = 2sinxcosx, tanx = sinx/cosx, cotx = cosx/sinx
sin2x(tanx+cotx)
=2sinxcosx(sinx/cosx + cosx/sinx)
=2(sin^2(x) +cos^2(x))
=2(1)
= 2
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