
William I. answered 04/21/22
Experienced Physics and Math Skills Tutor...patient and expressive.
B = 5.5 * 10-5T Δ A1=1.13*m2 A2 = 0 * m2
ΔA =A1-A2 = 1.13 * m2 and Δt = 2*s
The induced Emf is equal to the change in flux. since B is constant, the change in crosssection of the area perpendicular to the B field controls the induced Emf.
Vinduced = - Δ Φ / Δ t
Vinduced = - B * ΔA/Δt
= - (5.5 * 10-5 * 1.13 m2 / 2*s
= 3.1 * 10-5 V