
Dayv O. answered 04/18/22
Attentive Reliable Knowledgeable Math Tutor
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sina-sinb=2cos[(a+b)/2]sin[(a-b)/2]
why- let a=x+y, b=x-y
then sina-sinb=sin(x+y)-sin(x-y)=[sinxcosy+cosxsiny]-[sinxxcosy-cosxsiny}
=2cosxsiny
and a+b=x+y+x-y=2x,,,,,, x=(a+b)/2
a-b=2y ,,,,,y=(a-b)/2