Verify the identity PLEASE HELP!!

Question

1/1- sinx + 1/1+sinx = 2sec^2 x

Answer 1

1/(1-sinx) + 1/(1+sinx)

put the two fractions over a common denominator

(1+sinx + 1-sinx)/((1-sinx)(1+sinx)

= (1+sinx + 1 -sinx)/(1 -sin^2(x))

= 2/(1-sin^2(x))

note that sin^2(x) + cos^2(x) = 1, and 1-sin^(x) = cos^2(x)

= 2/cos^2(x)

= 2sec^2(x)