I need help with this stoichiometry question

Question

CAH8(g) + 6 02(g)

4 CO2(g) + 4 H20(g)

How many liters of carbon dioxide gas can

be created if I start with 45.63 grams of

oxygen gas?

Answer 1

45.63g / 32.00 g/mol = 1.426 mol

1.426 mol O₂ x (4 mol CO₂ / 6 mol O₂) = 0.9506 mol CO₂

Now use PV = nRT to solve for liters of CO₂ (V). I would assume that if no other information is given, P = 1 atm and T = 298 K. You can look up the value for R. It will be the one that has atm in its units (if you use atm for P because your units must cancel each other).