Mark M. answered 04/11/22
Tutor
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Retired math prof. Very extensive Precalculus tutoring experience.
Recall that sin(2θ) = 2sinθcosθ
So, 3sin(4x) / sinx = 3(2sin(2x)cos(2x)) / sinx = 6sin(2x)cos(2x) / sinx = 6(2sinxcosx)cos(2x) / sinx
= 12cos(2x)cosx