Let θ = sin-1x and φ = cos-1y Note that tanθ = x/sqrt(1-x2) and tanφ = sqrt(1-y2)/y by making the theta triangle have height x and hypotenuse 1 and the phi triangle have base y and hypotenuse 1.
tan(θ+φ) = (tanθ + tanφ)/(1-tanθtanφ)
Now sub in and simplify the mess.