Inactive Tutor answered 04/06/22
The relationship is C = Q / V,
capacitance is the charge stored per volt
and the unit is farads, F
C = (120 uC) / 6.0 v = 20 uF
V = Q / C can be solved similarly.
Q =64 uC
C = 20 uF
where u = mu = micro = 10^-6
Ysa K.
asked 04/06/22The charge stored on each plate of a capacitor is 120 μC when it is connected to a source with a potential difference of 6.0 V.
(a) What is the capacitance of the capacitor?
(b) What is the potential difference across the capacitor if the charge on each plate is 64 µC?
Inactive Tutor answered 04/06/22
The relationship is C = Q / V,
capacitance is the charge stored per volt
and the unit is farads, F
C = (120 uC) / 6.0 v = 20 uF
V = Q / C can be solved similarly.
Q =64 uC
C = 20 uF
where u = mu = micro = 10^-6
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