If you are using a Gaussian surface (a long cylinder of radius R (which we want to solve for) and length, L, and make the assumption that E is purely radial, Gauss's Law states that
EA = Qenc/εo For the uniform E field around the wire
A = 2πRL Qenc = λL where λ is the charge per length of wire. and ε0 is the electrical permittivity of free space.
E(2πRL) = λL/εo
Rearranging t solve for R:
R = λ/(2πRεo) and plug in the givens in appropriate SI units.