A 0.456 kg piece of iron is at an inital tempeerature of 29.5 C . If 87.3 J of thermal energy is removed from the piece of rion what is the final temperature

Answer 1

q = m x c x (change in temp)

c is heat capacity. The heat capacity of iron is 0.450 J/gC

-87.3 J = 0.456 kg x (1000 g / 1kg) x 0.450 J/gC x (change in temp)

-87.3 J / 456 g / 0.450 J/gC = -0.425 C

29.5 C - 0.425 C = 29.1 C

Answer 2