Jordan M.
asked • 03/23/222d/momentum inalastic collision
A 7.50 kg bowling ball moving
6.42 m/s strikes a 1.60 kg bowling
pin at rest. After, the ball moves
5.43 m/s at a 12.0° angle. What is
the x-component of the pin's final
velocity?
Can someone please give me a solid thourgh answer for this ,I would so greatly appreciate it!!
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1 Expert Answer
Momentum before the collision:
po = M*v
po = 7.50*6.42
po = 48.15 Ns in x direction
After the collision, the ball has a velocity of: 5.43*cos(12) = 5.31 m/s
Momentum Conservation
po = p1 in x-direction
M*v = m*vpx + M*vbx
(m-pin mass, M-ball mass, vpx-pin velocity after collision, vbx - ball velocity after collision) all in x-direction
48.15 = 1.60vpx + 7.50*5.31
vpx = 5.20 m/s
Jordan M.
Could you give me the y component as well sir ,I would really appreciate it?
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03/28/22
Jordan M.
That being the y component of the pins final velocity
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03/28/22
Rodrigo F.
tutor
Sure,
For y-axis:
poy = 0 (ball's velocity before the collision is zero)
py = m*vpy + M*vby
0 = 7.50*5.43sin(12°) + 1.6*vpy
vpy= -5.29 m/s
Let me know if you understood.
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03/28/22
Jordan M.
Yes I did sir ,thank you so much .I appreciate your thourgh answers not many people on her go as far as to do that .Please if you see my questions pop up answer them if you will !:)
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03/29/22
Rodrigo F.
tutor
Thanks, Jordan. I'll try to look for your questions. Send me if you can.
Best for you
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03/29/22
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Khush P.
Are you saying that the 7.5 kg ball is moving 5.43 m/s at a 12° angle afterward?03/23/22