Energy of a Charged Capacitor

Question

How large of a voltage source is required to store 0.025 J of energy on a 200 μF capacitor?

Answer 1

To solve this question, use the formula Energy = 1/2CV²

Also, remember to convert the units for capacitance to the base units, which means to convert 200 μF into

200 x 10^-6 F. We can also convert 0.025 J to 2.5 x 10^-2 J.

And we will plug and chug using the formula:

2.5 x 10^-2 J = (1/2)(200 x 10^-6 F)(V)²

2.5 x 10^-2 J = (100 x 10^-6 F)(V)²

250 = (V)²

V = 15.81 Volts