Honey C.

asked • 03/16/22

I really can't understand this one.... A stone is thrown by a man on top of a tower 300ft high

A stone is thrown by a man on top of a tower 300ft high directly towards a target located 200ft from the foot of the tower on the ground. If the stone leaves his hand with a velocity of 60fps, find the distance the stone will miss the target. Neglect the effect of air friction.


Answer: 99ft

Michael M.

So the stone is being thrown directly at the target, which gives us an angle at which the stone is being thrown. This angle can be found using some trig. It should land on the ground some distance in front of the target. It's asking you to find that distance.
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03/17/22

Christopher B.

tutor
Oh that's a different take - I just assumed a horizontal throw. Poorly worded question.
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03/18/22

1 Expert Answer

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Christopher B. answered • 03/18/22

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1) Determine the time for the object to hit the ground (must assume voy = 0)

2) Use that time with the equation vx = dx /t : Solve for dx

3) Subtract 200 ft from dx and take the absolute value to find distance from the target.


Edit: Much different/harder question if you interpret it as Michael M did in their comment. Once you do the trig to find the vertical and horizontal speeds that way, the process would be the same.

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