The period is proportional to the orbital radius to the 3/2 power.
Te = 1 year
T/Te = (r/re)^3/2 = (1.89)^1.5 = 2.60 years
Ebenezer I.
asked 03/16/22An asteroid is discovered in a nearly circular orbit around the Sun, with an orbital radius that is 1.89 times Earth's. What is the asteroid's orbital period in terms of Earth years?
The period is proportional to the orbital radius to the 3/2 power.
Te = 1 year
T/Te = (r/re)^3/2 = (1.89)^1.5 = 2.60 years
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Ebenezer I.
Thank you so much, sir. You really simplified this for me.03/16/22