Ebenezer I.
asked • 03/16/22An asteroid is discovered in a nearly circular orbit around the Sun, with an orbital radius that is 1.89 times Earth's. What is the asteroid's orbital period in terms of Earth years?
Douglas C. answered • 03/16/22
Retired Harvard Environmental Physics Prof
The period is proportional to the orbital radius to the 3/2 power.
Te = 1 year
T/Te = (r/re)^3/2 = (1.89)^1.5 = 2.60 years
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Ebenezer I.
Thank you so much, sir. You really simplified this for me.03/16/22