
Mark M. answered 03/14/22
Mathematics Teacher - NCLB Highly Qualified
A(t) = 0.6(1 - 0.0115)t
a(60) = 0.6(0.9885)60
Liyah C.
asked 03/14/22A tumor is injected with 0.6g of Iodine-125, which has a decay rate of 1.15% per day. Write an exponential model representing the amount of Iodine-125 remaining in the tumor after t days. Then use the formula to the amount of Iodine-125 that would remain in the tumor after 60 days.
Mark M. answered 03/14/22
Mathematics Teacher - NCLB Highly Qualified
A(t) = 0.6(1 - 0.0115)t
a(60) = 0.6(0.9885)60
Raymond B. answered 03/14/22
Math, microeconomics or criminal justice
A(t) = 0.6e^-0.0115t where t= number of days
A(60) = 0.6e^-0.0115(60) = 0.6e^-0.69 = 0.6(.5)= 0.3 g
1/2 = e^-.0115t
.5 = e^-.0115t
ln(.5) = -.0115t
t = ln(.5)/-.0115= about 60.27 days
t = = half life=about 60 days
in 60 days the amount left is slightly less than half of .6g = .3 grams
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