
Anthony T. answered 03/05/22
Patient Science Tutor
You need to calculate the energy released when 3000 grams of water cools from 100 C to 0 C. This is given by the equation Q = c x mass x temperature change (100 - 0) where c is the specific heat of water.
Once you have that, you can equate it to the heat absorbed when ice at 0 C melts.
This looks like Q = heat of fusion of ice x mass of ice, then solve for the mass of ice. You need to look up the values for the specific heat of water and the heat of fusion for ice in the correct units.