Anthony T. answered • 03/03/22
Tutor
5
(53)
Patient Science Tutor
I am not sure what is meant by 7.00 c/muC, but the electric potential at the points indicated can be computed using
V = kQ/R where k is the coulomb constant of 8.99 x 10^9, Q is the charge in coulombs, and R is the distance from the origin in meters. If you plug in the correct value for the charge, this should give you the answer.
Isidra C.
So it would be like this? (9m,8m): d=\sqrt{\left(9.00\right)^2+\left(8.00\right)^2} =\sqrt{81.0+64.0} =\sqrt{145} =12.0 V=(8.99 x 10^9) (7.00 x 10^-6)/(12.0) =5.24 x 10^3
Report
03/04/22
Anthony T.
You got it!
Report
03/04/22
Isidra C.
Thank you very much!
Report
03/05/22
Isidra C.
How about in this one Sir Anthony? Under a high-tech microscope, a scientist is studying 2 protons in the nucleus of a Uranium atom. He noted that they are 9fm apart. What is the potential energy (in J) associated with the electric force that acts between these two particles? What formula would I use, is it the same as what I use for the problem above?
Report
03/05/22
Isidra C.
Sorry I mean it's 7.00μC03/04/22