Lisa B.

asked • 03/03/22

Average speed and distance

A cyclist was intially was riding at 10km/hr for about 30minutes then he slowed to an average speed of 8km/hr and reached his destination in a further 1 hr .how far did the cyclist travel

Araoye I.

tutor
The only issue here is consistency of units. You only need the total of the distance of cycling 10 km/hr for half an hour plus the distance of cycling 8 km/h for 1 hour.
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03/03/22

1 Expert Answer

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Vishal S. answered • 03/21/22

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Math & Science Tutor | MD Student

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Remember here that average speed = distance/time. Let's divide the cyclist's journey into two parts.


For the first part (fast): distance= speed*time = (10 km/hr)(30 min) = (10 km/hr)(0.5 hr) = 5 km

For the second part (slower): distance = speed*time = (8 km/hr)(1 hr) = 8 km


In total, the cyclist traveled 8km + 5km = 13km

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