x^2-6x+13=0

Question

find or approximate solutions to the equation.  round to three decimal places if necessary.

Answer 1

ax² + bx + c = 0
x₁₂ = (-b ± √D) / 2a , D = b² - 4ac

x² - 6x + 13 = 0
a = 1 , b = (-6) , c = 13
D = (-6)² - 4 · 1 · 13 = -16
x₁₂ = (-(-6) ± 4i) / 2 ---> x₁₂ = 3 ± 2i