Combined Gas Law

Question

A sealed bottle containing 3.0 liters of air at a temperature of 20°C and a pressure of 2.0 atmospheres is taken outside where the temperature is 38°C. What is the new pressure?

Answer 1

P₁V₁/T₁ =P₂V₂/T₂ using the universal gas law. Since V₁=V₂ then P₂ =P₁T₂/T₁ putting in the values for P₁ =2 atm T₁ = 293 °K T₂ = 311°K P₂ = 2•293/311 = 1.88atm.