The key to rotational problems is understanding the analogy between translational equations and rotational equations. Kinematics: rot var * R = var at rim and Dynamics I is substituted for m. Also, torque is F x Lever arm and angular momentum is F x mv.
a) You are given ω0, ω = ω0/2, t = 6.4 s so you can find α (const acceleration process)
By analogy with v = v0 + at , you write ω = ω0 + αt or α = (ω-ω0)/t in rad/s2 Depending on your teacher, deceleration can be positive, but the equation will give a negative rotational acceleration because ω < ω0
b) Now, by analogy to F = ma , you write τ = Iα substitute in τ=FR and I = 1/2 MR2 for the cylinder and you get FR = 1/2 MR2α
I'll leave you to do the rest, Solve for F given all the rest and your answer to (a). Note that the force will be negative.