You can use the analogy with the kinematic equations of motion. This is a rotational acceleration process and you know t, ω0 (the initial rate of angular velocity = 0 rad/s), and Δθ = 3 revs = 6π radians
This is like finding v knowing v0, t, and d: The equation you would need is ((v+v0)/2)t = d = Δx
The analogous rotational equation is
((ω+ω0)/2)t = Δθ
zeroing ω0 and solving for ω:
ω = 2Δθ/t