Write an equation in​ slope-intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. ​ (-5,2);y=1/5x-3

Answer 1

First we find perpendicular slope (m)

slope of y=1/5x-3 is 1/5

Perpendicular slope is -1/5

Therefore, m=-1/5

Next we use the point slope form formula

(y-y1)=(x-x1)m

Plug in the point and slope and solve for y

y-2=(x-(-5))*(-1/5)

y=-x/5+1