A 405 kg roller coaster car is traveling at a constant speed of 12 m/s over a hill with a radius of curvature of 40 m.
(a) Calculate the net centripetal force acting on the car
(b) What is the normal force acting on the car at the top of the hill?
(c) What is the maximum speed (critical velocity) that the car can safely travel over the hill?
Keka K. answered • 02/03/22
Physics Chemistry Tutor
a) ∑Fc = mv2/r = (405)(12)2 / 40 = 1458 N
b). ∑Fc = Fg - Fn
1458 = 4050 - Fn.
Fn = 2592 N
c) Critical speed is when Fn = 0 ∑Fc = Fg - Fn.
∑Fc = Fg
mv2/r = m g.
v = √(rg) = 20 m/s
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