College Algebra

Question

A newspaper carrier has ​$6.85 in change. He has eight more quarters than dimes but two times as many nickels as quarters. How many coins of each type does he​ have?

How many quarters?

How many nickles?

How many dimes?

Answer 1

Q = 8 + D

D = Q -8

N = 2Q

N + D + Q = 685

2Q + Q-8 + Q = 685

4Q = 685+ 8 = 693

Q = 693/4 = over 173

D= over 165

N= over 346

173+ 165 + 346 = 684

best answer is 346 nickels, 165 dimes and 173 quarters.

Odds are the problem really had total value as $6.84 not $6,85