Bri S.
asked • 01/30/22A positively charged particle Q1 = +35 nC is held at fixed position
A positively charged particle Q1 = +35 nC is held at fixed position. A second charge Q2 of mass m = 3.5 μg is located a distance d = 25 cm directly above charge Q1. The net force on Q2 is equal to zero. You may assume this system is close to the surface of the Earth.
-->Calculate the magnitude of Q2 in units of nanocoulombs.
| I came up with an equation (|Q2| = ( m g d2 )/( k Q1 ) |
but after plugging in the given variables I get 6.820 * 10( - 18 )| which is wrong and I'm not sure why
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1 Expert Answer
Equation is good! I get 10-12 as exponential part, not 10-18. Everything must be in MKS
The one that probably got you was m = 3.5 micrograms = 3.5 x 10-9 kg
d = .25 m
Q = 35 x 10-9 C.
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Anthony T.
I derived the same equation as you, but I got a result of 6.82 x 10^-3 NC. Check your units to be sure they are Kg, m, and Coulombs in the calculation before converting to nC.01/31/22