Physics grade 11 kinematics

Question

1. A man tosses a chromebook out the window. The window is 3.18m above the ground, and the chromebook is thrown at 2.71m/s at an angle of 31.0 ̊ above horizontal.

i) How high up will the chromebook go, relative to the ground below (so, max height)?

Answer 1

y = 3.18 + 2.71sin31°t - 4.9t²; dy/dt = 2.71sin31° - 9.8t = 0; t = 2.71sin31°/9.8 = 0.14 s

max h = y(0.14) = 3.18 + 2.71sin31°·0.14 - 4.9·0.14^{2 = 4.48 m}